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DesertSnow

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Oct 10, 2007
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I think that this number defines the ratio

number of units that spawn reducing the barbarian power in a province by x / x

in other words, how many barbarian units are created per barbarian power lost in a province.

Am i correct?
 
I believe a province with 10 barbarian power will spawn a horde of 9(or 10) leaving 1 BP leftin the province. I have however seen 40 barbs spawn from a province with 12 bp... that wasn't exactly amusing, but i guess it was simply a bug.
 
DesertSnow said:
I think that this number defines the ratio

number of units that spawn reducing the barbarian power in a province by x / x

in other words, how many barbarian units are created per barbarian power lost in a province.

Am i correct?

I don't have much of an idea about how barbarians spawn in empty provinces.

In provinces which are owned by a civilization, spawn_horde = x produces x * y barbarian units where y is the barbarian power.
 
TheLand said:
In provinces which are owned by a civilization, spawn_horde = x produces x * y barbarian units where y is the barbarian power.

I assume that last means the barbarian power of the province. You've no idea what the BARBARIAN_POWER_MULT in defines.txt does?
 
Okay, according to a dev (podcat) it seems to work like this:

spawn_horde = X barbarian_power = Y BARBARIAN_POWER_MULT = Z

X x (Y x Z) = horde size. So by doubling the B_P_MULT, you'd double the number of units in any given horde, regardless of barbarian_power.
 
battlecry said:
Okay, according to a dev (podcat) it seems to work like this:

spawn_horde = X barbarian_power = Y BARBARIAN_POWER_MULT = Z

X x (Y x Z) = horde size. So by doubling the B_P_MULT, you'd double the number of units in any given horde, regardless of barbarian_power.

That (more or less) was what i thought. Thanks again, Battlecry.