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Serrith

Recruit
Mar 29, 2018
6
0
Description
Polymer Factory always produces 3 per shift [Win10]


Windows


Steam

What is your game version?
228,184

Please explain your issue is in as much detail as possible.
When I assign 1 worker in the polymer factory it produces 3 polymer per sol and if I assign 6 workers in the factory it also produces 3 polymer per sol. The daily production (predicted) changes but if I check how much polymers I produced last sol it's always 3 per shift.

Can you replicate the issue?
Yes, also when I start a new game.

Attachments
 
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Upvote 0
It's like you don't need to assign more then one worker per shift to the factory because it doesn't change how much it produces. Has someone else noticed this too?
 
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Can confirm for that the Polymer Factory produces 3 Polymers/shift, independent of the number of assigned workers. I didn't have the same bug on a Machine Parts Factory.
 
Devs i know you guys are fixing things atm but plz respond if you're going to fix this. It's like I'm playing the game with a cheat that only needs one worker per shift for the factory. The worker is getting lonely :p
 
This also happens to me. I suspect it happens to pretty much everyone, as I had noticed before that the polymer production report was always in multiples of 3, but I assumed it was a bug with the report, not with the production. After stumbling across this bug report I tested it and indeed the production report is accurate, and the factory info panel is misleading.

Plz Fix!
Thanks for a great game! =D
 
I *think* it has to do with the fact that machine parts factory and electronic parts factory both have this method :

ElectronicsFactory.OnCalcProduction_Electronics(producer, amount_to_produce)
return MulDivRound(producer.parent.performance, amount_to_produce, 100)

And the polymerplant doesn't, so performance is not taken into account.

Confirm, adding this works, I'm pushing a fix on the workshop in the mean time :
function PolymerPlant.OnCalcProduction_Polymers(producer, amount_to_produce)
return MulDivRound(producer.parent.performance, amount_to_produce, 100)
end

https://steamcommunity.com/sharedfiles/filedetails/?id=1364446023
 
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