Yes, I got too much time on my hands. luckily 1.02 just came so that can be fixed.
To make the table tad bit more readable, I'm substituting
K = Knight
LC = Light Cavalry
P = Pikemen
HI = Heavy Infrantry
A = Archers
LI = Light Infrantry
The orginal table i did was faulty, use an excellent one made by gratianus instead:
So, how is that monstrosity read?
Always multiply a number by the percentage amount of power of the social class in question. Sum together all the number*power% of a single troop type, and divide by the sum of number*power% of all troops in the unit to find out how much of the unit will be composed of that special troop type.
Also, if all troop types are summed up, the total numbers can be compared: That is, on feudal system giving all power to the nobles results in total troop amount of 5 and giving it all to peasants gives amount of 2. So full noble power in feudal system gives 2½ times the troops you'd get with full peasant power.
Examples, better make a lot of them:
First, the standard Traditional law on plains with 25% for each class.
Amount of:
Pikemen (1*0.25)/(2*0.25+2*0.25+3*0.25+3*0.25) = 0.25/2.5 = 1/10
Archers, knights and LI like Pikemen.
HI (0.25+0.25+0.25+0.25)/2.5 = 1/2.5 = 2/5
LC (2*0.25)/2.5 = 0.5/2.5 = 1/5
Giving as a grand total of 1 so I didn't do too much errors.
Just to use a little harder numbers, Feudal with 30% burghers, 10% peasants, 60% Nobles.
Knights: (2*0.6)/(2*0.1+2*0.3+5*0.6) = 1.2/3.8 = 6/19 ~32%
LI: (1*0.1+2*0.6)/3.8 = 1.3/3.8 = 13/38 ~34%
Pikemen: (1*0.1)/3.8 = 0.1/3.8 = 1/38 ~3%
Archers: (1*0.3)/3.8 = 0.3/3.8 = 3/38 ~8%
HI as Archers
LC as Knights
Also, the feudal 10/30/0/60 regiment is (3.8-2.5)/2.5 = 52% larger than the first example.
To make the table tad bit more readable, I'm substituting
K = Knight
LC = Light Cavalry
P = Pikemen
HI = Heavy Infrantry
A = Archers
LI = Light Infrantry
The orginal table i did was faulty, use an excellent one made by gratianus instead:
So, how is that monstrosity read?
Always multiply a number by the percentage amount of power of the social class in question. Sum together all the number*power% of a single troop type, and divide by the sum of number*power% of all troops in the unit to find out how much of the unit will be composed of that special troop type.
Also, if all troop types are summed up, the total numbers can be compared: That is, on feudal system giving all power to the nobles results in total troop amount of 5 and giving it all to peasants gives amount of 2. So full noble power in feudal system gives 2½ times the troops you'd get with full peasant power.
Examples, better make a lot of them:
First, the standard Traditional law on plains with 25% for each class.
Amount of:
Pikemen (1*0.25)/(2*0.25+2*0.25+3*0.25+3*0.25) = 0.25/2.5 = 1/10
Archers, knights and LI like Pikemen.
HI (0.25+0.25+0.25+0.25)/2.5 = 1/2.5 = 2/5
LC (2*0.25)/2.5 = 0.5/2.5 = 1/5
Giving as a grand total of 1 so I didn't do too much errors.
Just to use a little harder numbers, Feudal with 30% burghers, 10% peasants, 60% Nobles.
Knights: (2*0.6)/(2*0.1+2*0.3+5*0.6) = 1.2/3.8 = 6/19 ~32%
LI: (1*0.1+2*0.6)/3.8 = 1.3/3.8 = 13/38 ~34%
Pikemen: (1*0.1)/3.8 = 0.1/3.8 = 1/38 ~3%
Archers: (1*0.3)/3.8 = 0.3/3.8 = 3/38 ~8%
HI as Archers
LC as Knights
Also, the feudal 10/30/0/60 regiment is (3.8-2.5)/2.5 = 52% larger than the first example.
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